A bacterium divides every 35 minutes. If a cu | vedclass

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(D) The bacterium divides every $35$ minutes. Given total time = $175$ minutes. Number of divisions $(n)$ = $\frac{175}{35} = 5$. Since one bacterium

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$32 	imes 10^5$ cells/ml

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(D) The bacterium divides every $35$ minutes. Given total time = $175$ minutes. Number of divisions $(n)$ = $\frac{175}{35} = 5$. Since one bacterium produces two cells per division (binary fission),the population grows exponentially according to the formula $N_t = N_0 	imes 2^n$,where $N_0$ is the initial concentration and $n$ is the number of divisions. Initial concentration $(N_0)$ = $10^5$ cells/ml. Final concentration $(N_t)$ = $10^5 	imes 2^5 = 10^5 	imes 32 = 32 	imes 10^5$ cells/ml.

$A$ bacterium divides every $35$ minutes. If a culture containing $10^5$ cells/ml is grown for $175$ minutes,what will be the cell concentration/ml after $175$ minutes?

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